SpringMvc中,普通类注入Service为null,解决方案

场景:使用Quartz定时器时,普通的java类需要注入spring的service类,在调用时报错!

解决方式:

    /**
     * 定时获取课程的service
     */
    @Autowired
    protected QuartzGetCourseService quartzGetCourseService = (QuartzGetCourseService) SpringContextUtil
            .getBean("quartzGetCourseService");

import org.springframework.beans.BeansException;
import org.springframework.beans.factory.NoSuchBeanDefinitionException;
import org.springframework.context.ApplicationContext;
import org.springframework.context.ApplicationContextAware;
import org.springframework.stereotype.Component;

/**
 * 在Spring 注解中，普通类获取@Service标记的方法或者bean对象
 *
 */
@Component
public class SpringContextUtil implements ApplicationContextAware {
    private static ApplicationContext applicationContext = null;

    @Override
    public void setApplicationContext(ApplicationContext applicationContext) throws BeansException {
        SpringContextUtil.applicationContext = applicationContext;
    }

    public static ApplicationContext getApplicationContext() {
        return applicationContext;
    }

    /**
     * 注意 bean name默认 = 类名(首字母小写) 例如: A8sClusterDao = getBean("a8sClusterDao")
     *
     * @param name
     * @return
     * @throws BeansException
     */
    public static Object getBean(String name) throws BeansException {
        return applicationContext.getBean(name);
    }

    /**
     * 根据类名获取到bean
     *
     * @param <T>
     * @param clazz
     * @return
     * @throws BeansException
     */
    @SuppressWarnings("unchecked")
    public static <T> T getBeanByName(Class<T> clazz) throws BeansException {
        try {
            char[] cs = clazz.getSimpleName().toCharArray();
            cs[0] += 32;// 首字母大写到小写
            return (T) applicationContext.getBean(String.valueOf(cs));
        }
        catch (Exception e) {
            e.printStackTrace();
            return null;
        }
    }

    public static boolean containsBean(String name) {
        return applicationContext.containsBean(name);
    }

    public static boolean isSingleton(String name) throws NoSuchBeanDefinitionException {
        return applicationContext.isSingleton(name);
    }

}

调用结束,测试可以获取Service.

借鉴文章地址找不到了!